Prove that a positive integer that ends in 325 can’t be the square of an integer.
I'm not sure how to even approach this, I know that $325 = 5^2 \cdot 13$ but that hasn't led me anywhere.
Thank you in advance!
2026-04-02 10:47:48.1775126868
Prove by contradiction integer ends with 325
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A square must leave remainder $0, 1, $ or $4$ when divided by $8$.
What is the remainder when an integer ending in $325$ is divided by $8$?