Prove $(\forall x (P(x) \to \exists y Q(x, y))) \to (\exists x P(x) \to \exists y Q(x, y))$

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What I did was to first assume

$$ \forall x (P(x) \to \exists y Q(x, y))$$ Assume a free variable $x_0$

then doing a universal quantifier elimination

$$P(x_0) \to \exists y Q(x_0, y)$$

Now assuming $P(x_0)$

Using implication elimination

$$ \exists y Q(x_0, y)$$

This is all I managed to do because I was unable to remove the final line from the scope of $x_0$ assumption since there is no quantifier for x. How should I proceed?