This is a very common fact used in various places, but as far as I know we can prove $\mathrm{rank}(B^TB) \leqslant \mathrm{rank}(B)$. How do we show the equality condition. Thanks.
2026-04-06 03:10:15.1775445015
Prove $\mathrm{rank}(B^T B) = \mathrm{rank}(B) = \mathrm{rank}(B^T )$.
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