Prove: $N$ is a submodule of $M \iff N$ is a kernel of some homomorphism.
$(\implies)$ Fix $N<M$, $\kappa:M \rightarrow M/N. \kappa$ is the canonical epimorphism. Then $N=\ker\kappa.$
How to prove the other direction?
Prove: $N$ is a submodule of $M \iff N$ is a kernel of some homomorphism.
$(\implies)$ Fix $N<M$, $\kappa:M \rightarrow M/N. \kappa$ is the canonical epimorphism. Then $N=\ker\kappa.$
How to prove the other direction?
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If $n,n'\in\ker\kappa$, then $\kappa(n+n')=\kappa(n)+\kappa(n')=0$, and therefore $n+n'\in\ker\kappa$. And if $r$ belongs to the ring that you are working with, then $\kappa(rn)=r\kappa(n)=0$, and therefore $rn\in\ker\kappa$.