prove recurrence relation has unique solution

60 Views Asked by At

Hi everyone doing my last practice problem for finals tomorrow. Would really appreciate if someone can help me understand what this problem is asking.

$$\mathtt show\, that\, a\, kth\,order\,relation\,with\,k,initial\,conditions\,has\,a\,unique\,solution$$

what does it mean by kth order and initial conditions?

1

There are 1 best solutions below

2
On BEST ANSWER

$k$th order means each term depends on the preceding $k$ terms. $k$ initial conditions means the values of the first $k$ terms.