Prove that $ 2^{6ℓ + 2} ≡ 4\pmod{18}$

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Prove that $2^{6ℓ + 2}≡ 4 \pmod{18}$ for $0\leℓ ∈ ℤ$.

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Hint: This follows from the fact that $$ 2^6 \cdot 4 \equiv 4 \pmod{18}. $$