Prove that a sequence of reals together with its limit is compact by cover

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I need to prove that the set $K =\{X_n: n\in\Bbb N\}\cup \{l\} $ is compact by covers. Where $ l=\lim_{n \to \infty} X_n$. Where $X_n$ is a sequence of values in $\mathbb R$.

I understand that there are 2 cases. Case 1) K is countable and finite, where G = {$G_i$}$_{i\in I} $ is an arbitrary cove of K then $G^* = {G_i}_{n}$ is a finte subcover G.

I need help analyzing the other case.

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hint

Assume $$K\subset \cup_{i\in I} O_i $$

then $$\exists j\in I \;:\; l\in O_j .$$

but $$l=\lim_{n\to +\infty} X_n $$

thus $$\exists N\in\mathbb N \;:\;n> N \;\; \implies \;\;X_n\in O_j $$

and $$K\subset (\cup_{p=0,1,2...N}O_p )\cup O_j $$

where $O_p $ is such that $$X_p\in O_p $$