Prove that $A^T A = I$ if $A$ is a square matrix with orthonormal columns.
I'm not sure how to approach it, any ideas/hints?
Prove that $A^T A = I$ if $A$ is a square matrix with orthonormal columns.
I'm not sure how to approach it, any ideas/hints?
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When you are computing a matrix multiplication, let's say for example, $AB$, to obtain the $(i,j)$-entry of the matrix, you compute the dot product of the $i$-row of $A$ with the $j$-column of $B$.
So, what is the $(i,j)$-entry of $A^tA$ if the columns of $A$ (also the rows of $A^t$) are orthonormal?