Let $a, b, c$ be integers.
$c\mid a-b$ implies $a-b = cm$, $m \in \mathbb{Z}$
$c \mid a+b$ implies $a+b = cn$, $n \in \mathbb{Z}$
$(a-b)+(a+b) = cm + cn = c (m+n)$
$2a = c(m+n)$
Then I have no idea.
Let $a, b, c$ be integers.
$c\mid a-b$ implies $a-b = cm$, $m \in \mathbb{Z}$
$c \mid a+b$ implies $a+b = cn$, $n \in \mathbb{Z}$
$(a-b)+(a+b) = cm + cn = c (m+n)$
$2a = c(m+n)$
Then I have no idea.
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In point of fact, this is false: $2\mid 3-1$, $2\mid 3+1$ and $2\nmid 3$.