Prove that $L^2(\mathbb{R})\to L^2(\mathbb{R}) $ by $Vf(t) = f(t-1),$ is an isomorphism

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we define $V:L^2(\mathbb{R})\to L^2(\mathbb{R}) $ by $$Vf(t) = f(t-1).$$ Then I'd like to show that $V$ is an isomorphism

Here's what I've got so far:

$$\left \langle vf(t), vf(t)\right \rangle=\int_{\mathbb{R}}f(t-1)\overline{f(t-1)} dt=\left \langle f(t), f(t)\right \rangle$$

so we have$$\|Vf\|=\|f\|$$ indeed, $V$ is one-to-one and we can easily show that $V$ is linear

How can I prove $V$ is surjective and $V^{-1}$ is continuous?

Thanks in advance.