Prove that linear combination of two 3D independent vector will form a plane rather than a Sold

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How could we prove that linear combination of two 3D independent vector will always form a plane rather than a Solid?

Regards, Tarun

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I can see two ways to answer your question.

Definition of a plane

A (vector) plane is by definition the set of linear combinations of two independent vectors.

A plane doesn't contain an open ball

It's again a question of definition. How do you define a solid? If you mean by a solid a subset of $\mathbb R^3$ which contains at least one open ball ("it should be able to contain some volume"), then you can prove that an open ball can't be contained in a plane.