prove that $O^{P^{'}}(G)=P^{G}=P[P,G]$.

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suppose that $G$ is finite group and $p$ is prime number.prove that if $P$ is a $p$-sylow subgroup of $G$ then $O^{p^{'}}(G)=P^{G}=P[P,G]$ which $P^{G}$ is normal closure of $P$ in $G$ .

any hint or guidance or references to study will be great,thanks.