Prove that partial derivative of the harmonic function is greater than zero if the function takes the maximum at a specific point in the boundary

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Let $u\in C^2(\overline{B(0,1)})$ be harmonic $\Delta u = 0$ and not constant and let the function $u$ attain its maximum at $e_1=(1,0\dots0)\in\partial B(0,1)$. The task is to prove that $\partial _{x_1}u(e_1)>0$.

MY ATTEMPT: since the function is harmonic and hence smooth, it follows immediately $\partial _{x_1} u\geq 0$ due to maximum principle. Then I tried to use the approach that is used to prove maximum principle of harmonic functions in general, i.e. to add to the function some term that would yield sharp inequality, for example:

$$w(x)=u(x)+\varepsilon \exp(-\lambda|x|^2) + C.$$

However, I still can't see why this approach wouldn't yield a constant function $u$.

Thank you in advance!