I am trying to prove that the following integral is almost surely finite.
Assume $X$ is a stochastic process such that $$ dX_t = \kappa (\theta - X_t)dt + \sigma\sqrt{X_t}dW_t . $$ I would like to prove that for $ n\in\mathbb{N} $ and $T>0$ we have that $$ \int_0^T |X_t|^ndt < \infty \quad\mathbb{P}-a.s. $$ I do not know whether it is true or not! Thank you in advance!
As mentioned here Does finite expectation imply bounded random variable?, it suffices to show that
$$ \int_0^T E[|X_t|^n]dt < \infty. $$
We will simply use Application of the Burkholder Davis Gundy inequality
This is the case here since $\sqrt{x}\leq |x|$ for all large enough $x$. So for $n\geq 2$, we bound
$$ \int_0^T E[|X_t|^n]dt \leq TCe^{CT}(1+\mathbb{E}|X_0|^n). $$
For $n=1$, we simply bound $E|X|\leq \sqrt{E|X|^{2}}$.