I know how to prove that for $\mathbb{Z}/n$ where $n$ is odd, but what should we do in case of $\mathbb{Z}$?
2026-03-29 04:53:38.1774760018
Prove that there does not exist group $G$ such that ${\rm Aut}(G)\cong \Bbb Z.$
144 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in ABSTRACT-ALGEBRA
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