Given a function $f(z) \in C$ that is analytic, prove that $g(z) = \overline{f(\bar z)}$ is analytic in the set $\{\bar z : z \in C \}$. This is for homework: tips would be appreciated.
2026-04-02 15:58:41.1775145521
Prove the complex conjugate of an analytic function is analytic in the set of conjugates.
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$f(z)=\sum a_nz^n$ analytic ,hence $g(z)=\sum \bar a_n z^n$ is analytic.