Prove the linearity of polynomials.

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I need to prove the following properties for any two polynomials $p,q$ and $\alpha \in \mathbb{C}$

$$(p + q)(x) = p(x) + q(x)$$ $$(\alpha p)(x) = \alpha(p(x))$$

First of all, these two properties was, for me, the definition of function arithmetic from my pre-calculus days. So my first instinct is that these properties follow directly from the definition of function notation.

Secondly, if I was still going to attempt a proof I think I would do it as follows

proof

let $p,q$ be the following operators

$$ p = a_n\left( \right)^n + \cdots + a_1\left( \right) + a_0$$ $$ q = b_m\left( \right)^m + \cdots + b_1\left( \right) + b_0$$

and now I'll add these operators, but here's where I'm at a loss because I don't know how to add operators. Can I just assume (w.l.o.g) $n > m$ to get

$$p + q = a_n\left( \right)^n + \cdots + (a_m + b_m)\left(\right)^m + \cdots + (a_1+ b_1) \left( \right) + a_0+ b_0$$

These properties seem way too obvious to have to have to be proved I guess. Or is there some nuance I'm missing.

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Maybe you can introduce some notation, and then use linear algebra:

If you rewrite $p(x)\ =\ a_n x^n\ +\ a_{n-1} x^{n-1}\ +\ ...+\ a_0$, to be:

$$p = (a_n\ a_{n-1}\ ...\ a_0)$$ $$x = (x^n\ x^{n-1}\ ...\ 1)$$

then you can just make $p(x) := px^{\top}$

Now you can add operators and prove $(p+q)(x) = p(x)+q(x)$ and $\alpha(p(x)) = (\alpha p)(x)$.

As you see it is all matter of how you define things and stay congruent.