Prove, with restriction, that $\pi\neq\sqrt{2}+\sqrt{3}$

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Assuming any commonplace, but rigorous, definitions and properties of $\pi$, what could be a simple, rigorous and non-numerical argument for the following inequality?

$$\pi\neq\sqrt{2}+\sqrt{3}$$

By simple I mean within the framework of a typical elementary analysis course at university, say, and thereby excluding deeper properties like transcendence etc.

By non-numerical, I mean arguments that avoid calculating approximations.

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Find a shape which contains a circle of diameter $1$ and has perimeter $\sqrt{2}+\sqrt{3}$. By some isoperimetric inequalities, this shows that $\pi < \sqrt{2} + \sqrt{3}$.