$A, B, C$ are subsets of a set $U$:
$A ⊆ B → A ∩ B$ $\nsubseteq$ $C$ $(1)$
$A ⊆ B ∨ A ⊆ C$ $(2)$
$A ∩ C ⊆ B$ $(3)$
I have to prove that this is valid:
$A ∩ B$ $\nsubseteq$ $C$ $(4)$
It is recommended to use this in our proof:
$X ⊆ Y ↔ X ∩ Y = X$ $(5)$
Should this be solved by mathematical induction or somehow else? I don't know what to do about that. Sorry for bad English. That is not my first language.
I'd solve it by cases on (2). If $A \subseteq B$, you're done by (1).
Suppose now that $A \subseteq C$ (6).
By (6) we can say $A \cap C = A$.
So by (3): $A \cap C = A \subseteq B$.
So $A \subseteq B$ holds.
By (1): $A \cap B \nsubseteq C$.