Suppose $U=\{(x_{0},x_{1},x_{2},...)\in F^\infty:x_{2k}=x_{0},x_{2k+1}=x_1\}$. Intuitively, the dimension should be two, since the space is uniquely defined by two values. How can I prove this?
2026-03-24 23:56:01.1774396561
Proving dimension of a subspace of $F^\infty$
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