Proving right identity and left inverse implies group

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Given G is a set with associative binary opeartion.

Given for any,$a,b \in G$ , there exists $a'$ in G such that $ be=b, $. And $a'a=e$ First i try to show that $eb=b$.

Given,

$be=b$

$beb=bb$

$b'beb=b'bb$

$b'beb=eb=b$

$b'beb=b$

$eb=b$

Now for any element c of set G i want to show that $ce=c$

$ce=cc'e=ec=c$

To show right inverse :

Given $a'a=e$, $a'aa'=ea'$ $a'eaa'=ea'$

$a'aa'=a'$

$a'aa'=a'e$

$aa'=e$ (i believe cancellation laws can be proved by using left inverse, so using them)

Is this correct ? Thank you