Proving that first derivative vanishes

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Let $f$ be a real function which is differentiable on some interval $[0,a]$ ($a>0$) that satisfies :

  • $f'$ is continuous on $[0,a]$
  • $f'(0)=f(0)=0$
  • $f(a).f'(a)<0$

It is asked to prove that $f'$ vanishes at some point $c\in (0,a)$.

My approach :

Without loss of generality (working with $-f$ to address the other case) Assume that $f(a)<0 $ and $f'(a)>0$.

Claim : there exists $c \in (0,a)$ such that $f(c) <f(a)$ (because otherwise $f'_g(a) \le 0$)

$f$ is continuous on $[0,c]$ thus $f$ takes the (intermediate) value $f(a)$ at some $d\in (0,c)$. We can then apply Rolle's theorem to $f$ on $[d,a]$ to get the sought result.

Comment :

It seems the conditions : $f'(0) = 0$ and the continuity of $f'$ on $[0,a]$ are unnecessary.

Any remarks, rectifications are welcome. Thanks.