How to find the integral solutions of $$ \ x^2 + y^2 =2z^2 $$ such that x,y are distinct and $$ z^2 < 2(min(x,y))^2 $$
This can be reduced to $$ a^2 + b^2 = 2 $$ such that a,b are rational numbers.
2026-04-09 00:47:59.1775695679
Quadratic Diophantine equation
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