Let $A$ be a symmetric matrix.
And we have the quadratic form:
$$(x-y)^TA(x-y)$$
Where we know that $||x - y||_2 \leq 1/3$ and $||x||_2, ||y||_2 \leq 1$
How can we derive an upper bound of the form:
$$|(x-y)^TA(x-y)| \leq c \cdot |x^TAx|$$
Let $A$ be a symmetric matrix.
And we have the quadratic form:
$$(x-y)^TA(x-y)$$
Where we know that $||x - y||_2 \leq 1/3$ and $||x||_2, ||y||_2 \leq 1$
How can we derive an upper bound of the form:
$$|(x-y)^TA(x-y)| \leq c \cdot |x^TAx|$$
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