Question about Green's relations $L , R$ of semigroup.

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Let $e,f$ be idempotent of semigroup $S$ .

If $eLf$ then $ef=f$ and $fe=e$ .

From $eLf$ we have some $x,y \in S$ .

Such that $xe=f$ and $yf=e$.

Then $fxe = ff = f = xe $.

Can I reduce above to $ fx = x $ then $x=f$ .

If I can it will be clear.

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Your semigroup $S$ is not necessarily cancellative, so no, you can't reduce it.

To show $ef=f$ and $fe=e$ given $e\mathcal Lf$ for idempotents $e$ and $f$, you indeed have some $x, y\in S^1$ such that $xe=f$ & $yf=e$. Then $ef=(yf)f=yf=e$ and $fe=(xe)e=xe=f$.