Question about how we define permutation group and symmetric group

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My instructor introduced the definition of permutation and symmetric group as follow:

Permutation group: On an arbitrary set $X$, the permutation group is all the bijection maps: $X\to X$.

Symmetric group: On a finite set $X=\{1,2,...,n\}$, the symmetric group is all the bijection maps $X\to X$. Based on this definitions, it appears to me that symmetric group and permutation group are really the same things except the following:

  1. One is permuting numbers and the other is permuting any arbitrary elements.
  2. Symmetric group is referring to finite set.

He mentioned that symmetric group is a subgroup of permutation group where symmetric group is only working with finite numbers. He also proofed a theorem that permutation group is isomorphic to symmetric groups, which appears fine to me based on his definition of groups but not ok on the definitions I found elsewhere.

Based on my understanding, a more standard way of thinking permutation group is to consider them as a subgroup of symmetric group where only contains SOME but NOT ALL permutations on a given set. Refer to this question.

This two kind of definitions seem very different to me and I'm not sure how I can connect these two together. Need clarification on whether this is just two different ways of understanding them or one of them is incorrect.

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You're correct in that permutation groups don't have to contain all permutations on $X$.

A permutation group on $X$ is a subgroup of the symmetric group on $X$. (however there can be many such permutation groups, but only one symmetric group)