I am looking at this question:
A stone is dropped into a river from a bridge 43.9 ill above the water. Another stone is thrown vertically down 1.00 s after the first is dropped. The stones strike the water at the same time. (a) What is the initial speed of the second stone?
I have the solution but one thing I don't understand is why the initial speed of the second stone isn't just 0 m/s?
If you're dropping something down, wouldn't the initial velocity start at 0 m/s and then increase as it falls?