If you have $$ \int_0^2 \int_0^{\sqrt{4 - x^2}} e^{-(x^2 + y^2)} dy \, dx $$ and you convert to polar coordinates, you integrate from $0$ to $\pi/2$) with respect to theta.
But, if you have $$ \int_{-6}^6 \int_0^{\sqrt{36-x^2}} \sin(x^2+y^2) \, dy \, dx $$ and you convert to polar coordinates, you integrate from $0$ to $\pi$ with respect to theta. Can someone explain to me why the bounds of integration with respect to theta are different in these two problems? I'm having a hard time figuring it out. It would be a lot of help. Thanks.
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