Question about power of square root

38 Views Asked by At

I am currently prepping for next year's math course. Currently, I am practicing complex numbers and I have come across something I don't understand.

The problem is how to write the following complex number in rectangular form: $(1+i)^{13}$

I know the argument(z) is $\dfrac{(13 \cdot \pi)}{4}$

but when trying to find modulus, the solution says it is $\sqrt{2}^{13}$. I follow this so far but I don't get what the rule is for the next step, which is $2^6 \cdot \sqrt(2)$. What is happening here?

Any help is very much appreciated!

2

There are 2 best solutions below

0
On

Hint: $x^{13}=x^{12} x = (x^2)^6 x$

1
On

The absolute value is$$\left|(1+i)^{13}\right|=|1+i|^{13}=\sqrt2^{13}$$and\begin{align}\sqrt2^{13}&=\sqrt2^{12}\times\sqrt2\\&=\left(2^{1/2}\right)^{12}\times\sqrt2\\&=2^6\sqrt2.\end{align}