Question on Indices and specifically solving for an indice that has the value "x"

Question

Trying to workout 3(3$^x$) = 27$^{2x}$

So far i have done the following,

3(3$^x$)= 27$^{2x}$ (3)(3$^x$) = 27$^{2x}$ (3)+$x$= (9$^x$)(3$^x$)

Cant see what to do next...

Thanks for any help!

Answer 1

$$3\cdot \left( { 3 }^{ x } \right) ={ 27 }^{ 2x }\\ { 3 }^{ x+1 }={ \left( { 3 }^{ 3 } \right) }^{ 2x }\\ { 3 }^{ x+1 }={ 3 }^{ 6x }\\ x+1=6x\\ x=0.2$$