Question on limit with square roots

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I am studying up on my calculus and I have found this limit and I am not sure how to approach this without using L'Hopital's Rule. I am guessing there is an issue with my algebra. Here it is. $$\lim_{x\to 0}\frac{\sqrt{x-x\sqrt{x+x^2}-x^2}}{\sqrt x}$$I am lost on this one! Please help me on this. Thanks.

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Note that $$\lim_{x\to 0}\frac{\sqrt{x-x\sqrt{x+x^2}-x^2}}{\sqrt x}=\lim_{x\to 0}\sqrt{\frac{x-x\sqrt{x+x^2}-x^2}{x}}$$Then we have $$=\lim_{x\to 0}\sqrt{1-\sqrt{x+x^2}-x}=1$$