Let $A$ be an $n \times n$ matrix with $\operatorname{rank}(A) = k$, what is the rank of ($\lambda A$) for some $\lambda \in \mathbb{R}$ ?
I think since $\lambda$ is just a scalar it won't affect the rank of the matrix, so the answer is still $k$ ?
Let $A$ be an $n \times n$ matrix with $\operatorname{rank}(A) = k$, what is the rank of ($\lambda A$) for some $\lambda \in \mathbb{R}$ ?
I think since $\lambda$ is just a scalar it won't affect the rank of the matrix, so the answer is still $k$ ?
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Good guess so far.
However, don't forget the special case where $\lambda =0$, of which case, the problem become what is the rank of $0\cdot A=0$.
When $\lambda \neq 0$, solution of $(\lambda A)x=0$ and the solution of $Ax=0$ is the same. That is the kernel is the same. By rank-nullity theorem, the rank remains the same, which is $k$.