Question relating to inverse proportionality.

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I just came across a question I can't seem to understand, perhaps it it worded wrong that I do not know. The question is:

$y$ is inversely proportional to $x^3y=44$, when $x=a$. Find $y$ when $x=2a$

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$$y\propto \dfrac{1}{x^3}$$

means $$y= \dfrac{\text{constant}}{x^3} \quad \text{or,} \quad yx^3 = \text{constant}$$

So $$y \cdot a^3 = y' \cdot (2a)^3 $$ $$\Rightarrow y' = \dfrac{y}{2^3} = \dfrac{44}{8}$$