$$\int_{-\infty}^{2} x^{-4}dx$$
Since its type 1 I let A = $-\infty$
$$\lim_{A\to-\infty} \int_{A}^{2} x^{-4}dx $$
$$\lim_{A\to-\infty} \frac{x^{-3}}{-3}\bigg|_{A}^{2} = \lim_{A\to-\infty} -1/3\big(\frac{1}{8} - \frac{1}{A^3}\big) = -\frac{1}{24} - 0 = -1/24$$
Why does wolfram tell me this is undefined?
The integral $\int_{-\infty}^{2} x^{-4}dx$ is divergent, since $\int_{0}^{2} x^{-4}dx$ diverges.