What is the thought process behind the second line of the following, namely that the sin of 3 theta equals +/- 1? Thank you.
$r = \sin(3\theta)$
$\sin3\theta = +- 1$
$3\theta = (2k+1)\frac{\pi}{2}$
...
What is the thought process behind the second line of the following, namely that the sin of 3 theta equals +/- 1? Thank you.
$r = \sin(3\theta)$
$\sin3\theta = +- 1$
$3\theta = (2k+1)\frac{\pi}{2}$
...
I suspect it means $-1\leq3\theta\leq1$.
The other likelihood is that there's some other part we're not seeing which prevents $\sin(3\theta)$ taking the non-unitary values, thereby enabling the deduction that $\sin(3\theta)=-1$ or $\sin(3\theta)=1$.