Nine persons go into a 3-carriage tram. Each person chooses the carriage at random. Which are the probabilities of the event: A : “There are 4 person in a carriage, 3 in another, and 2 in the other one”?
The answer should be $\frac{280}{729}$
2026-04-03 05:53:39.1775195619
Random Multinomial Variable
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1
Answer to your question is $$\frac{\frac {9!}{4!3!2!}}{3^9}=0.0640146...$$