In general, if there are n nodes, there exist (2n)!/(n+1)! different tree
Is it possible to define an order function os(r,n) = rth structure of binary tree, where n = node count and r E (0, (2n)!/(n+1)!].
In general, if there are n nodes, there exist (2n)!/(n+1)! different tree
Is it possible to define an order function os(r,n) = rth structure of binary tree, where n = node count and r E (0, (2n)!/(n+1)!].
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