Rate of change of the radius of a balloon

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"Helium is pumped into a spherical balloon at a rate of $4$ cubic feet per second. How fast is the radius increasing after $3$ minutes?"

So this is what I did:

$$V = \frac{4}3\pi r^3$$

$$\frac{dv}{dt} = 4\pi r^2\frac{dr}{dt}$$

$$4 = 4\pi r^2\frac{dr}{dt}$$

$$\frac{dr}{dt} = \frac{4}{4\pi r^2}$$

I did not know how to proceed after this. How am I supposed to find the value of $r$? Do I have to somehow relate $3$ minutes ($180$ seconds) in somehow?

Any help?

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The volume is increasing at a constant rate.

$$\frac{dV}{dt}=4$$

and also $V(0)=0$.

Hence, at time $t=3$, you can compute the volume at that time and you can use the formula

$$V=\frac{4}{3}\pi r^3$$

to solve for $r$ at that time.