Ratio problem solving- ten machines use 200 kW

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Ten machines use 200 kilowatts to operate for 5 days, 10 hours per day. Determine the number of kilowatts used if they work for 3 days, 8 hours per day?

and the answer has to be in kW

updated

would it be

200kw /130hrs = x/80hrs

1600/130 = 130x

123= x


I did fractions with cross multiplying and got x= 71.4 kW but I know I am wrong.

5/3 + 10/8 = 200 kW/ x

40/24 + 30/42 = 200kW/ x

70/24 = 200kW/ x

70x = 5000 kW/70

x= 71.4 kW

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The unit of energy is the kilowatt-hour or some such. Kilowatts are a measure of power. As such, the duration of operation does not matter. If ten machines use $200$ kW, they use $200$ kW no matter how long they run. It is possible the point of the problem is for you to notice the difference between kilowatts and kilowatt-hours.

If the problem means $200$ kWh for $10$ machines, $5$ days, $10$ hours/day, that is $50$ hours of operation, so a $4$ kW power level. $3$ days, $8$ hours/day is $24$ hours, so they would consume $96$ kWh.