I am doing a proof that uses the $Re\{\}$ function (the function that outputs the Real part of a complex number $a + bi$). Along the way I realized that I am not sure how the function behaves when it comes to multiplied inputs. Specifically, is
$Re\{\phi_1 • \phi_2\}$ where $\phi_1, \phi_2$ are complex numbers equivalent to $Re\{\phi_1\} • Re\{\phi_2\}?$
Since $$(a+bi)(c+di) = (ac-bd)+(ad+bc)i$$ we have that $$\operatorname{Re}(zw) = \operatorname{Re}(z)\operatorname{Re}(w) - \operatorname{Im}(z)\operatorname{Im}(w).$$