I just need help getting started so I think I only need help with one of these.
I'm given,
{$x \in \mathbb{R} \ | \ x<0 \ or \ x>1 $}
I know I need to find some open ball (or more simply an open subset) s.t. every element of this subset is contained in the set ($-\infty,0$) and (1,$\infty$)
If I prove that both of these sets are open then I know that the union of the sets must be an open set.
So I create an open ball ($p_0 - r , p_0+r$) $\in$ ($-\infty,0$)
Then I let some $p \in (p_0 - r , p_0+r)$
I want to show that $p \in (-\infty,0)$
Is it enough to show then that p is strictly less than 0?
Thank you in advance.
Let $f:x\mapsto x (x-1) $ from $\Bbb R \to \Bbb R.$.
$f $ is continuous at $\Bbb R$, so the preimage of the open $(0,+\infty)$, which is the set $\{x\in \Bbb R \;\;:\; x <0 \lor x>1\} $ is an open.