I am looking the rearrange the equation to get h2 as the subject.
$$8-3.5 = (0.028)(h2 - 2724.9)$$
Now i have been dividing h2 both sides to get
$$\frac{4.5}{h2} = (0.028(h2 - 2724.9)$$
But this doesnt seem right. Can anyone help please
I am looking the rearrange the equation to get h2 as the subject.
$$8-3.5 = (0.028)(h2 - 2724.9)$$
Now i have been dividing h2 both sides to get
$$\frac{4.5}{h2} = (0.028(h2 - 2724.9)$$
But this doesnt seem right. Can anyone help please
$$8-3.5 = (0.028)(h2 - 2724.9)$$ $$8-3.5 = 0.028h2 - 76.2972$$ $$8-3.5+76.2972=0.028h2$$ $$80.7972=0.028h2$$ $$h2=\frac{80.7972}{0.028}$$ $$h2=2885.61$$