Reasoning behind statement L(P1) > L - (1/2)ε

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Hey Guys I'm studying this proof in real analysis and just this one line gets me:

Suppose that f is bounded and Riemann integrable on [a,b] and ε > 0 is given. Since L = sup{L(P): P is a partition on [a,b]} exists, there is a partition P1 of [a,b] such that

L(P1) > L - (1/2)ε

What exactly does this statement mean? and where does the 1/2 come from? I'm so confused

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It is just the definition of supreme. If $L<\infty$ is the supremum of a set $A$ of real numbers then

$$\forall \epsilon >0 \exists a\in A : a>L-\epsilon.$$

Since $\epsilon$ is arbitrary the result holds for $1/2\epsilon.$

Probably you have encountered this in the middle of a proof and the reason for $1/2\epsilon$ is technical. Sure there is another term in the proof with the same $1/2\epsilon.$ Thus, when you add both terms you get the "familiar" $\epsilon.$