Reducing a fraction with the denominator as a root.

Question

I have always been terrible with these, but how does $\frac{-36}{\sqrt{3^5}}$ equal $\frac{-4}{\sqrt{3}}$ ?

completely butchered the latex... I have -36/(root3)^(5) where the exponent is in the denominator. This equals -4/root3.

Answer 1

Hint: $\sqrt{3^{5}}=\sqrt{3^{4}\cdot3}=3^{2}\sqrt{3}=9\sqrt{3}$ . Also note $\frac{36}{9}=4$