What would be the integral of $\sin^n(x)$ under the limits $0$ and $\pi/2$, using reduction formula? I've got :
$$I(n) = \frac{n-1}{n}I(n-2)$$
Is this right?
2026-03-25 17:31:55.1774459915
Reduction formula to $\sin^n(x)$
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