Relation between kernels of homomorphisms and the semidirect product of groups

717 Views Asked by At

I'm reading Abstract Algebra of Dummit and I got stuck on this point. When we try to build the semi-direct product of 2 group predefined, such as $H$ and $K$, then all the semi-direct product groups is determined by the homomorphism from $K$ to $\operatorname{Aut}(H)$. The problem is to determine which couple of result groups are isomorphic to each other.

For example, we have 2 homomorphisms $\varphi_{1}, \varphi_{2}$. In some problems they reason that if $\operatorname{Ker}(\varphi_{1}) \cong \operatorname{Ker}(\varphi_{2})$, then 2 semidirect product groups of $H$ and $K$ defined by $\varphi_{1}$ and $\varphi_{2}$ are isomorphic, too. Can any one please explain for me whether this is true in general? If not, in which case this is true, and how to prove that?

One more thing, if two kernels are not isomorphic, how can we prove that two semidirect product groups are not isomorphic?

Thanks so much.