Relationship between measurable functions which induce the same pushforward measure

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Given a measure $\mu$ on some measure space $X$ and a measurable functions $f:X\to Y$ we can define a measure $f_* \mu(A)=\mu(f^{-1}(A))$ on $Y$.

If $f=g$ almost everywhere then $g_*\mu =f_*\mu$.

I could show that the converse holds by placing assumptions on $Y$ (i.e two real valued random variables with the same law are equal almost surely). Is the converse true more generally?

So far I have the supposition $g_*\mu =f_*\mu$ is equivalent to the measure of the symmetric difference of $f^{-1}(A)$ and $g^{-1}(A)$ being $0$. However with no other structure on $Y$ I am not sure whether more can be said.

My question is whether the converse is true. If not, are there any general sufficient measure theoretic conditions for it to be true?

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Obviously false. If $\mu \equiv 0$, then for any $f,g$, $f_*\mu = g_*\mu$.

Less trivially, let $\mu$ be the counting measure on a finite set $X$. Let $f:X \to \mathbb{C}$ be a function and $g = f\circ \sigma$ for some permutation $\sigma \in S_X$. Then $f_*\mu = g_*\mu$, but $g$ isn't necessarily $f$.