Representation of Heisenberg Algebra

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I tried one problem from "Introduction to Lie Algebras” by Karin Erdmann and Mark Wildon and there is one question that I am not sure how to do.

"Let $L$ be a Heisenberg lie algebra with basis $f,g,z$ such that $[f,g]=z$, and z lies in the center of $L$. Show that there is no finite dimensional faithful irreducible representation of L."

My attempt so far is as follows:

Assume that $V$ is a finite dimensional faithful irreducible representation of $L$. So there is an injective lie algebra homomorphism $\phi:L\rightarrow gl(V)$. It is easy to check that the set $z\cdot V=\{\phi(z)(v)|v\in V\}$ is an $L$ submodule of $V$. Since $V$ is irreducible representation of $L$, it follows that either $z\cdot V=\{0\}$ or $z\cdot V=V$. However, $z\cdot V\neq\{0\}$ because $\phi$ is an injective map. Therefore, $z\cdot V=V$.

I am not sure how to continue from here. Are there any hints how to proceed from here?

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Since the Heisenberg Lie algebra is nilpotent, it is also solvable. By Lie's theorem, every finite-dimensional irreducible representation of a solvable Lie algebra is $1$-dimensional. On the other hand, the minimal dimension of a faithful representation of the Heisenberg Lie algebra is $3$. Hence there is no finite-dimensional faithful irreducible representation of the Heisenberg Lie algebra.

References:

Are all irreducible representations of solvable Lie algebras 1-dimensional?

Faithful representation of the Heisenberg group