$$8y^2+96y-12x+240=0$$
I'm not sure how to approach that problem because there's a $\frac23y^2$ to deal with
It sounds like you need to rewrite it in the form $$(y-k)^2=4p(x-h),$$ for some constants $h,k,p$. As a hint: start with $8y^2+96y=12x-240$ and complete the square on the left-hand side (after dividing everything by $8$, if you prefer).
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It sounds like you need to rewrite it in the form $$(y-k)^2=4p(x-h),$$ for some constants $h,k,p$. As a hint: start with $8y^2+96y=12x-240$ and complete the square on the left-hand side (after dividing everything by $8$, if you prefer).