Riemann Prime Counting Function:
The second correction/paring terms:
I tried to use Mathematica function LogIntegral to plot this second correction/paring terms, for example, when I only include the first 2 non-trivial zeros, and plot with range x from 1 to 5:

Plot[Sum[LogIntegral[x^ZetaZero[k]] + LogIntegral[x^(1 - ZetaZero[k])], {k, 1, 2}], {x, 1, 5}]
However, I got very large value instead of small correction:
I can also use simplified equation provided by[ ref 1]:
Plot[Sum[Exp[ZetaZero[k]*Log[x]]/(ZetaZero[k]*Log[x]), {k, 1, 2}] + Sum[Exp[(1 -ZetaZero[k])*Log[x]]/((1 - ZetaZero[k])*Log[x]), {k, 1, 2}], {x, 1, 5}]
Then I got the correct result:
Anyone knows what is wrong for the LogIntegral one?
Thank you!

![sum_(rho)li(x^rho)=sum_(I[rho]>0)[Li(x^rho)+Li(x^(1-rho))]](https://i.stack.imgur.com/gIMd1.png)



